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nordsb [41]
3 years ago
12

*HELP PLEASE* WILL GET BRAINLIEST ANSWERRRR!!!

Mathematics
2 answers:
erica [24]3 years ago
6 0
I believe the first bag is $5.03 per pound and the second bag is $4.86 per pound so the second bag is the better deal. Good luck!
Nikitich [7]3 years ago
5 0

Hi!

so what you want to do is take the price and divide it by the pounds.

11.98/2.38 = $5.03 per pound

19.49/4.01 = $4.86 per pound

the better buy is the 4.86 per pound

Hope this helps!

You might be interested in
A recipe calls for 14 cups of flour and 6 cups of sugar. Will the two recipes be proportional if the recipe decreases to 7 cups
Eduardwww [97]

The two recipes are proportional to each other.

<u>Explanation:</u>

Given:

Amount of flour initially = 14 cups

Amount of sugar = 6 cups

Ratio of flour to sugar initially = 14 / 6

                                                 = 7 : 3

Changed amount of flour is 7 cups

Changed amount of sugar = 3 cups

So,

14 - x = 7

     x = 7

6 - y = 3

    y = 3

The ratio of flour to sugar after changing the amount = 7 : 3

Therefore, the two recipes are proportional to each other.

8 0
4 years ago
PLEASE PLEASE HELP ME I REALLY NEED HELP
Gekata [30.6K]

Answer:

(a) yes it does

(b) the rate is constant because the rate of change (slope) is the same throughout the function.

(c) The rate, or rate of change, is -1/2.

y1 - y2/x1-x2

4 - 2/3 - 9

2/-6

-1/2

7 0
4 years ago
I need urgent help with the question. Can someone please give full working out of the attached question
Bumek [7]

Answer:

2x-2

Step-by-step explanation:

Being specifically asked to rationalise the denominator we focus on it as required.

To rationalise a term it has to be multiplied by its inverse.

The inverse of

\sqrt{x}  -  \sqrt{2 - x}

is

\sqrt{x}  +  \sqrt{2 - x}

Multiplying this two vives us a difference of two squares

{( \sqrt{x} })^{2}  -  {( \sqrt{2 - x} )}^{2}

which gives us

x-(2-x)

=2x-2

8 0
3 years ago
About 50% of babies born with a certain ailment recover fully. A hospital is caring for six babies born with this ailment. The r
Sergio [31]

Answer:

a. yes it is a binomial experiment

b. success is that baby recovers

c. n = 6

d. p = 0.5

e. q = 0.5

f. X: 0,1,2,3,4,5,6

Step-by-step explanation:

a.

the answer is<u> </u><u>yes</u><u> </u><u>this</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>bino</u><u>mial</u><u> </u><u>experiment</u><u>.</u><u> </u>This is true because we have a finite number of babies and these babies are independent of each other. there are two possible outcomes. 1. baby recovers 2. baby does not recover.

b.

success: baby recovers

c.

n = number of babies born with ailment. n = 6

d.

p = 50% = 0.5

e.

q = 1-p = 1-0.5

q = 0.5

f.

possible values of X: 0,1,2,3,4,5,6

7 0
3 years ago
An ambulance travels back and forth at a constant speed along a road of length L. At a certain moment of time, an accident occur
Sergio [31]

Answer:

The distribution of distance of ambulance from accident is \frac{2(L-a)}{L^2}\\

Step-by-step explanation:

  • Let X and Y be the random variables associated as

               X=Position of Ambulance on Road

               Y=Location of Occurrence of Accident

It is known about X & Y that

  1. X & Y are normally distributed
  2. X & Y independent of each other.

The joint density function is given as

                                     f(x,y)=f_X(x)f_Y(y)=\frac{1}{L^2}

This is true for (x,y)∈(0,L^2) otherwise it is equal to zero.

  • Let Z be the random variable giving distance between X and Y so

                                           Z=|X-Y|

  • The cumulative distribution of Z is given as

                              P(Z\leq a)=1-P(Z>a)\\

Here  P(Z>a) is given as following on basis of the 2-d plot of X & Y points such that their difference is greater than a variable a.

                              P(Z>a)=\frac{(L-a)^2}{L^2}

Substituting in the above equation

                          P(Z\leq a)=1-P(Z>a)\\P(Z\leq a)=1-\frac{(L-a)^2}{L^2}\\

Now fZ(a) is given as

                         f_Z(a)=\frac{d}{da}P(Z\leq a)=\frac{2(L-a)}{L^2}\\

So the distribution of distance of ambulance from accident is \frac{2(L-a)}{L^2}\\

6 0
4 years ago
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