Answer:
the volume of sand is ![50 ft^{3}](https://tex.z-dn.net/?f=50%20ft%5E%7B3%7D)
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, rectangular prism.
Given data
![Length l= 4 ft Width w= 5ft\\Height h = 3ft](https://tex.z-dn.net/?f=Length%20%20l%3D%204%20ft%20Width%20w%3D%205ft%5C%5CHeight%20h%20%3D%203ft)
if the sandbox is filled with sand of
deep the volume of the sand in the box will be calculated based on the the depth of the sand
converting the depth of sand from mixed fraction to proper fraction we have ![2\frac{1}{2} = \frac{5}{2}](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B5%7D%7B2%7D)
the expression for the volume of a rectangular prism is
![volume of sand = length * width* height](https://tex.z-dn.net/?f=volume%20of%20sand%20%3D%20length%20%2A%20width%2A%20height)
substituting our data into the expression we have
![volume of sand= 5*4 * \frac{5}{2} \\volume of sand = \frac{100}{2} \\volume of sand = 50 ft^{3}](https://tex.z-dn.net/?f=volume%20of%20sand%3D%205%2A4%20%2A%20%5Cfrac%7B5%7D%7B2%7D%20%5C%5Cvolume%20of%20sand%20%3D%20%5Cfrac%7B100%7D%7B2%7D%20%5C%5Cvolume%20of%20sand%20%3D%2050%20ft%5E%7B3%7D)
5^3(5^x) the rule is a^b(a^c)=a^(b+c)
5^(3+x)
Answer:
hi
Step-by-step explanation:
28.5
The weight of the full steel bead tire in pounds is 1.76 pounds
The weight of the lighter steel bead tire in pounds is 1.54 pounds.
<h3>What are the weights of the tires?</h3>
Division is the process of dividing a number into equal parts using another number. The sign used to denote division is ÷.
The weight of the full steel bead tire in pounds = 800 / 453.592 = 1.76
The weight of the lighter steel bead tire in pounds = 700 / 453.592 = 1.54
To learn more about division, please check: brainly.com/question/13281206
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Answer:
A solid figure whose bases or ends have the same size and shape and are parallel to one another, and each of whose sides is a parallelogram.
Step-by-step explanation: