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Assoli18 [71]
3 years ago
7

The National Health Interview Survey conducted of 33,326 adults by the U.S. National Center for Health Statistics in 2003 indica

ted that 21.4% of adults were current smokers. A similar study conducted in 1991 of 42,000 adults indicated that 25.6% were current smokers. We will use the subscript "1" for the year 1991 and the subscript "2" for the year 2003. (a) Find a point estimate of the difference between the proportion of current smokers in 1991 and the proportion of current smokers in 2003. Use 3 decimal places.
Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer: 0.042

Step-by-step explanation:

Point estimate of the difference between the two population proportion p_x-p_y :-

\hat{p}_x-\hat{p}_y , where \hat{p}_x and \hat{p}_y are sample proportions.

Given : In 1991 survey , The proportion of adults were current smokers =25.6%

i.e. \hat{p}_x=0.256

In 2003 survey , The proportion of adults were current smokers = 21.4%

i.e. \hat{p}_y=0.214

Then , the point estimate of the difference between the proportion of current smokers in 1991 and the proportion of current smokers in 2003 :-

\hat{p}_x-\hat{p}_y=0.256-0.214=0.042

Hence, a point estimate of the difference between the proportion of current smokers in 1991 and the proportion of current smokers in 2003= 0.042

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