Answer:
a
n = 4
n + 33
Step-by-step explanation:
n = number of jumps after the 0 term of '33'
aka: add 4 to the previous number
We just need to find the multiples of 9 that are greater than 20.
9*1 = 9
9*2 = 18
9*3 = 27
9*4 = 36
9*5 = 45
We can use 27,36, 45, .....
Your final answer should be any multiple of nine greater than 20. I recommend using 27, 36, and 45. Hope this helps!<span />
732.4 because just put in a decimal before a # and then do place value to a whole #.
