1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga55 [171]
3 years ago
11

Find the area of circle B in terms of pie

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

area of circle= πr²

π = 22/7

r=1.5

A =22/7 ×1.5²

A =7.07yd²

morpeh [17]3 years ago
3 0
In terms of pie the answer is d . 2.25
You might be interested in
If w = -2 and v = -8, which of the following expressions shows the values correctly substituted in for the variables in the expr
ki77a [65]

Answer:

the first one

(-2) 2-(-8)+1

3 0
3 years ago
Read 2 more answers
What is the value of x in this equation: 4x + 5 = 3x + 4? Solve the equation using the algebra tiles. x =
Leno4ka [110]

Answer:

Solution of the equation 4x + 5 = 3x + 4 is:

x= -1

Step-by-step explanation:

We are given a equation:

4x + 5 = 3x + 4

We have to solve the equation for x

4x+5=3x+4

subtracting both sides by 4

4x+5-4=3x+4-4

4x+1=3x

subtracting both sides by 4x

4x|+1-4x=3x-4x

1= -x

⇒ x= -1

Hence, solution of the equation 4x + 5 = 3x + 4 is:

x= -1

5 0
4 years ago
Read 2 more answers
Help meeeeeeeeeeeeeeee​
laila [671]

Answer:

D.

Step-by-step explanation:

Complementary angles are two angles whose measures add to 90°.

A.

m<CFD = 150° - 100° = 50°

m<EFD = 180° - 150° = 30°

Sum = 80°

No

B.

m<AFB = 40°

m<DFE = m<EFD = 30°

Sum = 70°

No

C.

m<AFC = 100°

Sum > 100°

No

D.

m<BFC = 100° - 40° = 60°

m<DFE = 30°

Sum = 90°

Yes

Answer: D.

8 0
2 years ago
Based on the data in the two-way table, what is the probability that a person weighs 120 pounds, given that he or she consumes 2
sdas [7]
<span>In the question "Based on the data in the two-way table, what is the probability that a person weighs 120 pounds, given that he or she consumes 2,000 to 2,500 calories per day?" The probability of an event, say A given another event, say B is given by n(A and B) / n(B). Thus the probability that a person weighs 120 pounds, given that he or she consumes 2,000 to 2,500 calories per day is given by number of persons that weigh 120 pounds and consume 2,000 to 2,500 calories per day / number of persons that consume 2,000 to 2,500 calories per day. From the table, the number of persons that weigh 120 pounds and consume 2,000 to 2,500 calories per day is 10 while the number of persons that consume 2,000 to 2,500 calories per day is 110. Therefore, the required probability is 10 / 110 = 1 / 11</span>
3 0
3 years ago
Read 2 more answers
You get $84 each month from your mom for your cell phone bill. The base fee each month is $27 plus $0.15 per minute. What is the
SCORPION-xisa [38]
So, to figure out this problem you first need to solve for how much you have left after paying the base fee. Take the total ($84) and subtract by the base fee ($27). You will get 57 as your answer. Then, take $57 and divide it by $0.15 to get your answer. It is 380 minutes each month. The equation here is 84=27+0.15x.
4 0
3 years ago
Other questions:
  • Given: ΔACM, m∠C = 90º
    8·2 answers
  • Help pleaseeeeeeeeeeeee!
    10·1 answer
  • What is 144% as a fraction
    11·1 answer
  • Please help ! I’ll give brainliest
    10·1 answer
  • In a certain manufacturing process, it is known that, on average, 1 in every 100 items is defective.
    13·1 answer
  • Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
    15·2 answers
  • What's the probability a dealer deals himself an ace on the first deal?
    14·1 answer
  • Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG
    11·1 answer
  • 10=z+6 plsss solve !!!!
    6·2 answers
  • 8= 1/4 (5x - 8)<br><br> Solve for x in simplest form.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!