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3 years ago

I WILL AWARD BRAINLIEST!

Mathematics

2 answers:

sammy [17]3 years ago

8 0

A)70 this is the answer

gavmur [86]3 years ago

7 0

Answer:

A. 70

Step-by-step explanation:

You can use the transversals and use vertical angles are congruent.

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If I have a price of 125 and there is a 20% discount, what is my price now?

mojhsa [17]

100 is your price now

3 0

2 years ago

Read 2 more answers

A retailer buys a coat in bulk at a unit price of $45. The coat is marked up to 28% to sell in the store. What is the price of t

Lostsunrise [7]

Answer:

57.60

Step-by-step explanation:

If the coat is marked up 28%, then the cost is increased by 28% to produce the selling price.

SP = 45 + 28/100 * 45

SP = Selling Price

SP = 45 + 28*45 / 100

SP = 45 + 1260 / 100

SP = 45 + 12.60

SP = 57.60

Answer: The selling price is 57.60

8 0

3 years ago

Jacob went on a fishing trip. This year he caught 30 fish, which is six more than twice the number he caught last year. How many

NARA [144]

Answer:

12 fish

Step-by-step explanation:

You need to work this problem backwards. If he caught 30 fish, which was six more than twice the number he caught last year, you would start by subtracting six, leaving you with 24. Then you'd have to divide by 2, because it was twice plus six as many fish, which would give you 12 fish.

$\frac{30-6}{2}$ = x

$\frac{24}{2}$ = x

12 = x

5 0

3 years ago

Pizzazz HELP MEEEE

Art [367]

Answer:

8x less than or equal to $50

Step-by-step explanation:

bc the x represents the amount of books you can get for 8 dollars per book and can be less than or equal to, but not greater than 50, the max amount you may spend

hope this helped :)

4 0

3 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago