All categories

3 years ago

The answer I don’t know how to do it

Mathematics

1 answer:

OlgaM077 [116]3 years ago

8 0

You must isolate C. See attached photo. Hope it helps. (Sorry it’s messy...written by finger on my phone.)

You might be interested in

How would i answer this?

Lelu [443]

9514 1404 393

Answer:

y = (x -1)² -16

Step-by-step explanation:

Note the location of the vertex (point A) on the graph. Its x-coordinate is readily identifiable as 1. Its y-coordinate is some value between -15 and -20, closer to -15. (If you go to the trouble of finding the vertex coordinates, you discover they are (1, -16).)

Once you have determined what the vertex is, you can compare the offered answer choices to the vertex form ...

y = (x -h)² +k

where (h, k) are the vertex coordinates. That is, you are looking for an answer choice that is something like ...

y = (x -1)² -16

3 0

3 years ago

What is the quotient when x3 − 5x2 + 3x − 8 is divided by x − 3? (2 points)

Alchen [17]

Answer:

Socratic app it will be over in the bank

5 0

3 years ago

Fifteen students are going hiking on their spring break. They plan to travel in three vehicles—one seating 7, one seating 5, and

andriy [413]

Answer:

The students can group themselves in 360360 ways

Step-by-step explanation:

For this exercise we need to use the following equation:

$\frac{n!}{n1!*n2!*...*nk!}$

This equation give us the number of assignation of n elements in k cell, where n1, n2, ..nk are the element that are in every cell

In this case we have 15 student that need to be assign in three vehicles with an specific capacity. This vehicles would be the equivalent to cells, so we can write the equation as:

$\frac{15!}{7!*5!*3!}$

Because the first vehicle have 7 seating, the second vehicle have 5 seating and the third vehicle have 3 seating.

Solving the equation we get 360360 ways to organized 15 students in three vehicles with capacity of 7, 5 and 3 seating.

5 0

3 years ago

Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30

Dafna11 [192]

Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

$\bf u=
\begin{cases}
x=7cos(330^o)\\
\qquad 7\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{7\sqrt{3}}{2}\\
y=7sin(330^o)\\
\qquad 7\cdot -\frac{1}{2}\\
\qquad -\frac{7}{2}
\end{cases}\qquad \qquad v=
\begin{cases}
x=8cos(30^o)\\
\qquad 8\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{8\sqrt{3}}{2}\\
y=8sin(30^o)\\
\qquad 8\cdot \frac{1}{2}\\
\qquad 4
\end{cases}$

$\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)
\\\\\\
\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~ \stackrel{b}{\frac{1}{2}}\right)\\\\
-------------------------------$

$\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}
\\\\\\
\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o$

8 0

3 years ago

The temperature in degrees Fahrenheit of a corpse t hours after death is 58+40e−t/2458+40e−t/24. What is the temperature of the

jolli1 [7]

Answer:

58+40e−t/2458+40e−t/24

step by step explanation:

Normally, the temperature of a corpse is the temperature of the surrounding environment.

This is done by losing or gaining heat to equilibrate to that of the surrounding.

Let's assume that the final temperature of the corpse is after t hrs.

Then the temperature of the surrounding in degree Fahrenheit is equal to 58+40e−t/2458+40e−t/24

7 0

3 years ago

Read 2 more answers