Graph the function y=4(2^x+3)-1 and y=-2(3^x-4)+1
1 answer:
The graphs of the functions y = 4(2ˣ + 3) - 1 and y = - 2(3ˣ - 4) + 1 are plotted on the graph.
<h3>What is function?</h3>A function is a relation between a dependent and a independent variable, such that the dependent variable depends upon the independent one for its existence.
Given are the following functions -
y = 4(2ˣ + 3) - 1
y = - 2(3ˣ - 4) + 1
We have the following functions -
y = 4(2ˣ + 3) - 1
y = - 2(3ˣ - 4) + 1
Refer to the graph attached. The graph of red color represents the function y = 4(2ˣ + 3) - 1 and the graph of blue color represents the function y = - 2(3ˣ - 4) + 1. It can be seen that the graphs are symmetrical about the line y = 10.
Therefore, the graphs of the functions y = 4(2ˣ + 3) - 1 and y = - 2(3ˣ - 4) + 1 are plotted on the graph.
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Answer:
No because it contains points (3,4) and (3,-4). You cannot have a x assigned to more than one y-value if you want it to be a function.
Step-by-step explanation:
A function has one output per input.
If we are trying to determine if the given is a function of x, then x is the input.
However I can get two outputs from plugging in x=3.
Subtract 9 on both sides:
Take the square root of both sides:
.
So input x=3 yields y=4 and y=-4.
Since this input has more than one output then the given is not a function of x.
----Also!
If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:
Subtract 25 on both sides:
Simplify:
There is only one value y such that when you square it gives you 0. That is 0.
x=5 only gives y=0 and x=-5 only gives y=0.
There is no circle, unless it is a circle with radius 0 which means it really wouldn't be a circle, that is a function.