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aliina [53]
3 years ago
13

A motorboat takes 3 hours to travel 144 km going upstream. The trip takes 2 hours going downstream. What is the rate of the boat

in still water and what is the rate of the current?
Rate of the boat still in water:

Rate of the current:
Mathematics
1 answer:
allsm [11]3 years ago
6 0
Let x be rate of boat in still water
let y be rate of current

we use this equation to relate quantities:
distance = speed · time

we have two unknowns so we might need to create a system of equationss

upstream:

speed (in km/h) = x - y
(we get speed of boat then subtract the current's speed from it since current is going against boat direction)

time = 3 hours

distance = 144 km

downstream:

speed (in hm/h) = x + y
(we get speed of boat then add the current's spd from it since current is going against boat direction)

time = 2 hours

distance = 144 km (same distance upstream and downstream)

using distance = speed times time

for upstream
144 =  3(x-y)
144 = 3x - 3y

for downstream
144 = 2(x+y)
72 = x + y

system of eqns:
144 = 3x - 3y
72 = x + y

solve by substitution: move 72 = x + y into x = 72 - y and subst into other equation for x

144 = 3(72 - y) - 3y
144 = 216 - 3y - 3y
144 = 216 - 6y
144 - 216 = -6y
-72 = -6y
y = 12 km/h

Use x = 72 - y to find x with y = 12: x = 72 - 12 = 60 km/h

rate of boat in still water is 60 km/h
rate of the current is 12 km/h
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3 years ago
A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
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600
m
i
2
h
r
=
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Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
2 years ago
Please help me! WILL MARK BRAINLIEST. Thanks!
galben [10]

Answer:

For the first table: (0, 10) (1, 15) (2, 20) (3, 25) (4, 30)

For the second table: (-2, 1.04) (-1, 1.2) (0, 2) (1, 6) (2, 26)

For the third table: (-2, 10) (-1, 0) (-1/2, -5/4) (1, 10)

Step-by-step explanation:

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How much icing is needed over the donut shown below (Diameter of 4in and 1.5in wide)
Dafna11 [192]
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5 0
2 years ago
Solve: 3(5x - 8) = 6x + 39
soldier1979 [14.2K]

Steps to solve:

3(5x - 8) = 6x + 39

~Distribute left side

15x - 24 = 6x + 39

~Add 24 to both sides

15x = 6x + 63

~Subtract 6x to both sides

9x = 63

~Divide 9 to both sides

x = 7

Best of Luck!

6 0
3 years ago
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