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wlad13 [49]
3 years ago
8

What is the solution to this equation?

Mathematics
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

Option (D)

Step-by-step explanation:

Given equation is,

8e^{2x+1}=4

Taking natural log on both the sides of the equation,

\text{ln}(8e^{2x+1})=\text{ln}(4)

\text{ln}(2^3)+\text{ln}(e^{2x+1})=\text{ln}(2^2)

3ln(2) + (2x + 1)[ln(e)] = 2ln(2)

2n(2) - 3ln(2) = (2x + 1)

2x = -ln(2) - 1

2x=\text{ln}(\frac{1}{2})-1  [Since, -ln(2) = ln(1) - ln(2) = \text{ln}(\frac{1}{2})]

2x=\text{ln(0.5)}-1

x=\frac{\text{ln(0.5)-1}}{2}

Therefore, Option (D) will be the correct option.

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