Answer:
Mean of sampling distribution = 5.10 alcoholic drinks per week
Standard deviation of the sampling distribution = 0.11
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 5.10 alcoholic drinks per week
Standard Deviation, σ = 1.3401
Sample size, n = 150
a) Mean of sampling distribution
The best approximator for the mean of the sampling distribution is the population mean itself.
Thus, we can write:

b) Standard deviation of the sampling distribution

2x*2 + 6x + 80
First we have to use distribution property
2(x*2 + 3x + 40)=0
Divide 2 to both sides
X*2 + 3x + 40=0
Multiply -1
-x*2 -3x-40=0
Add two numbers to get 3x
Multiply same two numbers that you add to get 40x*2
Add
-8x+5x= -3x
Multiply
-8x . 5x= -40x*2
-x*2-8x+5x-40
(X*2-8x) + (5x-40)
X(x-8)+ 5(X-8)
Common factor
(X-8)(x+5)
This would help you!
The following table shows the total number of quizzes taken in high school. how many quizzes are taken per week?