Answer:
4.R=16
D=16+16=32
C=
C=32π
then do the same thing for other problem
Cars= C Trucks= T
$3C + $5T = $785
Answer:
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Step-by-step explanation:
We can have two expressions to show the total cost paid by a member and non-member;
Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per summer season=$105
Cost per number of times they rent a boat=$9.50
Number of times they rent a boat=n
Replacing;
Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1
Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per number of times they rent a boat=$14.75
Number of times they rent a boat=n
Replacing;
Total cost by a non-member=(14.75×n)=14.75 n......equation 2
To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2
9.5 n+105=14.75 n
14.75 n-9.5 n=105
5.25 n=105
n=105/5.25
n=20
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
-0.6(-6.3)
When 2 numbers are side by side it is a multiplication problem.
Multiply -0.6 by (-6.3)
-0.6 x -6.3 = 3.78
