Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:

Then, the probability that at most 1 car will require major engine repair next year is:

Answer:
hope it helps man
eeeed
Step-by-step explanation:
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Answer: X ≤ 6
Step-by-step explanation:
Answer:
(2,-2)
Step-by-step explanation:
y=-4x+6
y=3x-8
plug the y's in for each other to get:
-4x+6=3x-8 <----- solve from there
+8 +8
-4x+14=3x
+4x +4x
14=7x
/7 /7
x=2
now plug the x in to get y (in any problem)
y=3(2)-8
y=6-8
y=-2
<em>(2,-2)</em>