In Exercise,find the balance in the account after 10 years.

Mathematics

1 answer:

Vesnalui [34]3 years ago

3 0

Answer: $ 3462.03

Step-by-step explanation:

The exponential equation for growth (compounded continuously) is given by :-

$A=Pe^{rt}$

, where P= Present value

r= growth rate ( in decimal)

t= time

As per given , we have

P=$1900, r = 6% =0.06 and t= 10

Substitute all the values in the above equation , we get

$A=1900e^{0.06(10)}$

$A=1900e^{0.6}$

$A=1900(1.8221188)=3462.02572\approx3462.03$ [To the nearest cent]

Hence, the balance in the account after 10 years = $ 3462.03

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HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$