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BARSIC [14]
3 years ago
11

5,25,125 find 10th term

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

9765625

Step-by-step explanation:

There is a common ratio between consecutive terms , that is

r = 25 ÷ 5 = 125 ÷ 25 = 5

This indicates the sequence is geometric with n th term

a_{n} = a₁r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 5 and r = 5 , then

a₁₀ = 5 × 5^{9} = 5 × 1953125 = 9765625

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What is the sum of this expression??<br><br> 3 3/7 + 1 6/7 = ???
Anna11 [10]

Answer:

5 2/7

Step-by-step explanation:

3 + 1 = 4

3/7 + 6/7 = 9/7 = 1 2/7

1 2/7 + 4 = 5 2/7

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Which of the following correctly describes the variation in the equation r=d/t?
maw [93]
Answer number 3 is correct.
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4. Asia is designing a triangular-shaped window with a height of 15 inches and
Anni [7]

Answer:

18in

Step-by-step explanation:

Given data

Height h= 15 in

Area= 135 in^2

The expression for the area is given as

Area= 1/2 Base * Height

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Base= 135/7.5

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Hence the base is 18in

3 0
2 years ago
Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars
dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = \dfrac{1}{5} \ car / min = 0.2 \ car /min

the rate of the buses = \dfrac{1}{10} \ bus / min = 0.1 \ bus /min

the rate of motorcycle = \dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min

The probability of any event at a given time t can be expressed as:

P(event  \ (x) \  in  \ time \  (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}

∴

(a)

P(2 \ car \  in  \ 20 \  min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}

P(2 \ car \  in  \ 20 \  min) =0.1465

P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}

P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422

P ( 0 \ buses  \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}

P ( 0 \ buses  \ in \ 20 \ min) =  0.1353

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

= 0.3333 \times \dfrac{1}{4}

= 0.0833

∴

P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}

P(zero  exact  change  in  10 minutes) = 0.4347

c)

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

P( 4  \ motorcyles \  in  \ 45  \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}

P( 4  \ motorcyles \  in  \ 45  \ minutes) =0.0469

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

d)

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

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P(no other vehicle  other vehicle arrives within 5 minutes is)

= \dfrac{6}{12} = 0.5

<u>For motorcycle:</u>

= \dfrac{2 }{12}  = \dfrac{1 }{6}

∴

The required probability = 1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!}  \Bigg)

= 1- 0.5134

= 0.4866

6 0
3 years ago
The measure of each interoir angle of a regualr polygon is 144 . how many sides does this polygon have
egoroff_w [7]
Each Interior Angle = 180 - (360 / number of sides)
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# of sides = -360 / (144 -180)
# of sides = -360 / -36
# of sides = 10












6 0
3 years ago
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