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miskamm [114]
3 years ago
8

How do I double the volume of a pyramid

Mathematics
1 answer:
Mumz [18]3 years ago
7 0
Any one of ...
1) double the height, or any other single dimension
2) multiply the base edge lengths, or any other pair of dimensions, by √2
3) multiply every dimension by ∛2
4) multiply the dimensions by any combination of numbers whose product is 2.
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Solve the equation for y y−5x=3
Lyrx [107]

Answer:

y = 5x + 3

Step-by-step explanation:

y - 5x = 3

add 5x to both sides to isolate y

y = 3 + 5x

rearrange to slope intercept form

y = 5x + 3

3 0
3 years ago
Ive been waiting hours for someone to answer this question. Is everyone an idiot.
stepan [7]

Answer:

D) x = -2/3 and x = 6

Step-by-step explanation:

4(x²−x+2)−(x+10)(x+2)           Distribute

(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20    Multiply

4x² + −4x + 8 + −x² + −12x + −20           Combine like terms            

(4x² + −x²) + (−4x + −12x) + (8 + −20)      Combine like terms

3x² −16x −12 = 0      

x = -2/3 and x = 6

I graphed the equation on the graph below.

If this answer is correct, please make me Brainliest!

7 0
3 years ago
Steve has 12 biscuits in a tin.
AfilCa [17]

Answer:

The asnwwer is

Have a Great Day

4 0
4 years ago
Which are are solutions for x^2 + 5x – 1 > 6
Eddi Din [679]

Answer:

it might be b and d

Step-by-step explanation:

6 0
3 years ago
Please help!! I’m not sure how to answer this question!!
nlexa [21]
<h3>Answer:  9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

\frac{1}{3}\pi*r^2*h

Let's plug in the given height h = 12 and we'd get

\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say V = 4\pi r^2

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\

The radius tripled which results in a volume that's 9 times bigger.

3 0
2 years ago
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