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3 years ago

How do I double the volume of a pyramid

1 answer:

7 0

Any one of ...
1) double the height, or any other single dimension
2) multiply the base edge lengths, or any other pair of dimensions, by √2
3) multiply every dimension by ∛2
4) multiply the dimensions by any combination of numbers whose product is 2.

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Circle A has a radius of 6 inches. Circle b has a radius 20% greater than circle A. What is the radius of circle B?

Ulleksa [173]

Answer:

7.2inches.

Step-by-step explanation:

Given parameters:

Radius of Circle A = 6inches

Unknown:

Radius of circle B = ?

Solution:

We are to find the radius of circle B.

The relationship between circle A and B is such that;

Radius of Circle B = 20% greater than that of A

Radius of Circle B = 1.2 x 6 = 7.2inches.

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3 years ago

Find the solution for s 9s + 3 = 57

torisob [31]

The solution is 6

9x6+3=57

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3 years ago

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What types of lines create alternate interior angles?

Softa [21]

C should be the correct answer

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3 years ago

Find the surface area of the figure below. Round your answer to the nearest hundredth if necessary,

olya-2409 [2.1K]

A= 2(w l + h l + h w) = 224m^2

7 0

3 years ago

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

So, no option is correct. And the answer is

$T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$

Learn more about linear transformations here-

brainly.com/question/13005179

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5 0

2 years ago