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4 years ago

How many units is 1 from -6 on a number line

1 answer:

8 0

Find this by subtracting the two terms and then finding the absolute value of the difference.

1-(-6)= 7
|7|= 7

Final answer: 7

You might be interested in

Someone please help really need it.

Pani-rosa [81]

Answer:

y=5x-13

Step-by-step explanation:

7 0

3 years ago

The health department estimates that eight vials of malaria Serum will treat 100 people. at this rate, how many vials are requir

lara [203]

Using butterfly method, it is 14 vials

5 0

3 years ago

What is the expectation for a binomial distribution with p = 0.5 and n = 8?

Natasha2012 [34]

Answer: 4

Step-by-step explanation:

Given the following :

P = probability of success = 0.5

n = number of trials = 8

The expected value of a binomial distribution with probability of success P and number of trials n is defined by:

E(n, p) = n * p

Therefore, expected value when P = 0.5 and n = 8

E(8, 0.5) = 8 × 0.5

= 4

The expected value of the binomial distribution is 4

8 0

3 years ago

A 15 foot pole extends & feet below ground and 10 feet above ground. Choose the

irakobra [83]

Answer:

There is no specific linear equation for this scenario because there is only one possible length for the pole.

Step-by-step explanation:

7 0

3 years ago

A marble is selected at random from a jar containing 3 red marbles, 4 yellow marbles, and 6 green marbles. What is the probabi

alexgriva [62]

Answer: a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

a) the marble is red?

Probability of getting a red marble = $\dfrac{3}{13}$

b) the marble is not yellow?

Probability of not getting yellow = $\dfrac{3+6}{13}=\dfrac{9}{13}$

c) the marble is either red or green?

Probability of getting either red or green = P(red) + P(green) = $\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}$

d) the marble is neither red nor green?

Probability of getting neither red nor green = P(getting yellow) = $\dfrac{4}{13}$

Hence, a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

5 0

3 years ago