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3 years ago

How to work out 18000÷120 on paper

Mathematics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

150.

Step-by-step explanation:

We can divide each number by 10 which simplifies the division to 1800 / 12.

Do the division:

12) 1800 ( 150 <------------ Answer.

12 Subtract 18 - 12:

60 <--- Gives 6 then we append the 0.

First we divide 12 into 18 which gives us 1 with a remainder of 6.

Bring down the next digit (0) to give 60 then 12 divided into 60 gives 5 exactly. Finally 0 / 12 = 0 and we get the answer 150.

GaryK [48]3 years ago

4 0

Answer:

Step-by-step explanation:

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Read 2 more answers

the arithmetic sequence ai is defined by the formula: a1 = -53 ai = ai-1 + 6 find the sum of the first 880 terms in the sequence

maxonik [38]

Answer:

The sum of the first 880 terms in the sequence is 2,273,920.

Step-by-step explanation:

Arithmetic sequence:

The difference between consecutive terms is always the same, called common difference, and the nth term is given by:

$a_{n} = a_0 + (n-1)d$

In which d is the common difference.

Sum of the first n terms:

The sum of the first n terms of an arithmetic sequence is given by:

$S_{n} = \frac{n(a_1+a_n)}{2}$

ai = ai-1 + 6

This means that $d = 6$

In this question:

Sum of the first 800 terms, so $n = 800$

First term is -53, so $a_1 = -53$

The 880th term is:

$a_{880} = -53 + (880-1)*6 = 5221$

Sum

$S_{n} = \frac{880(-53+5221)}{2} = 440(-53+5221) = 2273920$

The sum of the first 880 terms in the sequence is 2,273,920.

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3 years ago