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Rashid [163]
3 years ago
7

Evaluate the expression -434 + (-1.5)2

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer: -437

Step-by-step explanation:

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Find the area of a circle with a circumference of 37.67 units
liberstina [14]

The circumference of a circle is pi x diameter. Therefore, we can use this in reverse order as well.

I’ll be using 3.14 as pi, but if you need a more exact answer you can always use the pi function on a calculator.

37.68/3.14 = 12

Therefore, the diameter must be 12.

Since the radius is half the diameter, we can divide by 2 to find the radius.

12/2 = 6

Therefore, the radius of our circle is 6.

The area of a circle is equal to pi x radius squared.

Since we know our radius, we can solve.

Using PEMDAS, we know to use exponents first, so 6 squared is equal to 36.

From there, we can multiply.

36 x 3.14 = 113.04

And there we have your answer! 113.04 is the area of the circle.

Hope this helped :)

5 0
3 years ago
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Composite figures are really confusing me and I need help
Darya [45]
All you do is 104 times 50 and then you get your anwser
3 0
3 years ago
Analyze the diagram below and complete the instructions that follow.
Flura [38]
This is an isosceles triangle, so both legs are of length 5√2.

Use the Pyth. Thm. to find the length of the hypotenuse.  Square 5√2 and double the result:  25(2) = 50; twice 50 is 100.  The square of the length of the hyp. is 100, and so the length of the hyp is sqrt(100), or 10 (answer).
4 0
3 years ago
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What value of x is in the solution set of 4x - 12 = 16 + 8x?<br><br> -10<br> -9<br> -8<br> -7
Georgia [21]

Answer: just use a calculator ._.

Step-by-step explanation:

7 0
3 years ago
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The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of
Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is,\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4

The standard deviation of this sample is 2. That is, s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2.

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5

The new mean is 5.

Compute the standard deviation of this sample as follows:

s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s

The new standard deviation is also 2.

5 0
3 years ago
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