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Juli2301 [7.4K]
4 years ago
9

Pls help. The figure below (picture) is a parallelogram. What is the length of n?

Mathematics
1 answer:
Elena L [17]4 years ago
4 0
The answer is 18 and that’s what I got I think
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IrinaVladis [17]

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B sin 9° = cos 81°

As both values is

0.156434465

7 0
3 years ago
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What are two factors that add up to the coefficient -13
Gala2k [10]

Answer:

1, 13

-1, -13

here are 2 coefficient factors that multipy to get 13

brain list please?

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3 years ago
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IF THIS IS GOOD THEN I WILL PROMOTE YOU SO GOOD AND WILL GIVE YOU BRANLIEST AND DONT DO THIS JUST FOR POINTS OR I WILL REPORT AN
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
babymother [125]

Answer:

The total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

Step-by-step explanation:

In mathematics, the procedure to select <em>k</em> items from <em>n</em> distinct items, without replacement, is known as combinations.

The formula to compute the combinations of <em>k</em> items from <em>n</em> is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

In this case we need to determine the number of ways in which the drugs are assigned to each mouse.

It is provided that new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes.

Drug A is to be given to 22 mice.

Compute the number of ways to assign drug A to 22 mice as follows:

{60\choose 22}=\frac{60!}{22!(60-22)!}\\\\=\frac{60!}{22!\times 38!}\\\\=14154280149473100

Now the remaining number if mice are: 60 - 22 = 38.

Compute the number of ways to assign drug B to 22 mice as follows:

{38\choose 22}=\frac{38!}{38!(38-22)!}\\\\=\frac{38!}{22!\times 16!}\\\\=22239974430

Now the remaining number if mice are: 38 - 22 = 16.

Compute the number of ways to assign no drug to 16 mice as follows:

{16\choose 16}=\frac{16!}{16!(16-16)!}\\\\=1

The total number of ways of assignment is:

N = {60\choose 22}\times {38\choose 22}\times {16\choose 16}\\\\=14154280149473100\times 22239974430\times 1\\\\=314,790,828,599,338,321,972,833,000

Thus, the total number of ways of assignment is 314,790,828,599,338,321,972,833,000.

8 0
3 years ago
Riley bought 50 foot or rope. He cut off pieces that total 34’8” so far. How much rope does he have left
Vedmedyk [2.9K]

Answer:

the answer is 15'2" of the rope that is left

Step-by-step explanation:

8 0
3 years ago
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