Do you have a calculator? you can solve it by substituting x.
y=16x^2
0: y = 16(0)^2 = 16(0) = 0
(x = 0 , y = 0)
0.5: y = 16(0.5)^2 = 16(0.25) = 4
(x = 0.5 , y = 4)
1: y = 16(1)^2 = 16(1) = 16
(x = 1 , y = 16)
1.5: y = 16(1.5)^2 = 16(2.25) = 36
(x = 1.5 , y = 36)
2: y = 16(2)^2 = 16(4) = 64
(x = 2 , y = 64)
2.5: y = 16(2.5)^2 = 16(6.25) = 100
(x = 2.5 , y = 100)
3 : y = 16(3)^2 = 16(9) = 144
(x = 3 , y = 144)
4: y = 16(4)^2 = 16(16) = 256
(x = 4 , y = 256)
if you multiply a negative number by itself, it will become positive. So, -4, -3, -2.5, -2, -1.5, -1, -0.5 will be the same as the positive 4, 3, 2.5, 2, 1.5, 1, 0.5.
I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.
Answer:
b. cos²3x - sin²3x = cos6x
if its wrong sorry
hope this helps you☺️☺️
So,
If the number in the ten-thousandth's place is greater than or equal to 5, then round up. If not, round down.
0.1325: Note the 5. We round up.
0.1325 --> 0.133
Answer:
8.69565217391 m per sec
8.7 (1dp)
Step-by-step explanation:
Answer:
The median, because the data distribution is skewed to the right
Step-by-step explanation:
If the longer part of the box is to the right (or above) the median, the data is said to be skewed right. If the longer part is to the left (or below) the median, the data is skewed left. The data is skewed right. The median would be a better estimate, because one or two numbers on the high end will cause the numbers to be skewed to the right, and the mean to be high