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Nadusha1986 [10]
3 years ago
10

QUESTION AND ANSWER IN IMAGE!

Mathematics
1 answer:
eduard3 years ago
8 0
That would be Graph C

The  solution is where the 2 graphs intersect  At A and B.  
x + y + 2 = 0  transforms to  y = -x - 2 which has slope -1 and  y-intercept of -2
as in Graph C.
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I need help plz help me what does Suspend mean like you account got suspend does it mean it's ban for ever
nasty-shy [4]

Answer:

no if your account got suspended  it means you have been banned for a while not forever

Step-by-step explanation:

3 0
2 years ago
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Given x^2 -4x+4 is a factor of the polynomial 2x^4 - 11x^3 +68x-80, completely factor the polynomial using algebraic methods.​
asambeis [7]
Answer:

2x^4-11x^3+68x-80

2x^4-4x^3-7x^3+14x^2-14x^2+28x+40x-80

2x^3(x-2)-7x^2(x-2)-14x(x-2)+40(x-2)

(x-2)(2x^3-7x^2-14x+40)

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(x-2)(2x^2(x-2)-3x(x-2)-20(x-2))

(x-2)(x-2)(2x^3-3x-20)

(x-2)(x-2)(2x^2+5x-8x-20)

(x-2)(x-2)(x(2x+5)-4(2x+5))

(x-2)(x-2)(2x+5)(x-4)

(x-2)^2(2x+5)(x-4)
4 0
3 years ago
Write an exponential function to describe the given sequence of numbers, assuming that the first number in the sequence correspo
Fantom [35]

Answer:

y = 5(6) {}^{x}

Step-by-step explanation:

A exponential function is represented by

y = ab {}^{x}

where a is the vertical stretch and b is the base and x is the nth

power of x

Since the first number corresponds with zero, that means our y intercept is the first number.

This means when x=0 , y=5 so let find the value of 5.

5 = ab {}^{0}

b to the 0th power equal 1 so

5 = a \times 1

a = 5

Our equation is for now

y = 5b {}^{x}

Now let plug in 1,30

30 = 5b {}^{1}

Divide 5 by both sides

6 = b {}^{1}

Anything to the 1st power is itself so b equal 6.

So our equation is

y = 5(6) {}^{x}

6 0
2 years ago
Describe a real world situauationthat could be modled by dividing two rational numbers
Dima020 [189]
You have 10 slices of cake, you and your friends Jerry, George, Martha, and Jenny ( just an example ) eat 2 slices of cake. 
A more real life one would be:
You have 6 bills to pay off, then two more come in, you only pay off 4, 
( I hope this helped, I'm sorry if any of this is wrong:) )
7 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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