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Gemiola [76]
3 years ago
8

3. Can a triangle have sides with the given lengths? 8 cm, 7 cm, 9 cm

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
6 0

Answer:yes

Step-by-step explanation:

Elza [17]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

In geometry, an isosceles triangle is a triangle that has two sides of equal length. Sometimes it is specified as having exactly two sides of equal length, and sometimes as having at least two sides of equal length, the latter version thus including the equilateral triangle as a special case. Examples of isosceles triangles include the isosceles right triangle, the golden triangle, and the faces of bipyramids and certain Catalan solids.

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Some help me please help me please help me please
kodGreya [7K]
1_ 210+90= 300



2_ it's prime:


[1,19]




good luck


4 0
3 years ago
A cereal box has a length of 8 inches, a width of 2 inches and a height of 12 inches. What is the volume of the cereal box?
DochEvi [55]

Answer:

192 in cubed

Step-by-step explanation:

Multiply 12*2= 24*8

6 0
3 years ago
Read 2 more answers
If you can answer this and show your work ill give brainly
Arlecino [84]

Answer:

First answer is 127 and second answer is 15

8 0
2 years ago
Read 2 more answers
How are all angles in the 4th quadrant, negative or positive?
anastassius [24]

Answer:

They are all positive because you must go right.

They are all negative because you must go down.

Step-by-step explanation:

Example. (1,-4)

You go over one.

Down 4

5 0
3 years ago
Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
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