2/5 of the population has blood type A. 23/50 have blood type O. What fraction of the population had either blood type A or O?

A triangular prism has a volume of 832m3. The area of the base is 64m2. What is the height of the prism?

dolphi86 [110]

Answer:

13 m

Step-by-step explanation:

volume=1/2(b×h)×length/height

height =volume÷base area(1/2b×h)

832÷64=13m

6 0

3 years ago

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

Given:

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

Solve for $x$ in the 1st equation:

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

Substitute the value of $x$ into the 2nd equation and solve for $z$ :

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

Substitute the value of $z$ into the 3rd equation and solve for $y$ :

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

Plug $y=3$ into the solved expression for $z$ and evaluate to solve for $z$ :

$z=16-7(3)$

$z=16-21$

$z=-5$

Plug $z=-5$ into the solved expression for $x$ and evaluate to solve for $x$ :

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

6 0

3 years ago

gail ran 4<img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D" id="TexFormula1" title="\frac{6}{10}" alt="\frac{6}{10}" ali

erastovalidia [21]

92/25=3.68 I hope this help

3 0

3 years ago

HELPPP!!!

madam [21]

Answer:

2 and a half @ 2.5 inches (sorry i can't type the fraction)

Step-by-step explanation:

english is my second language so sorry if you doesn't understand:

(1/2, 1/4)=(x,y)

based on the graph shown that each grid on the y axis represents 1/4, that is the smallest scale stood in the y axis.

this means 2 grid= 1/4 x 2 = 1/2 @ 0.5 inches.

since the '5 months-hair-length' is above about 2 grid above 2 inch:

2 inch + 0.5 inch= 2.5 inch

4 0

3 years ago

Please help me. I need help please.

Mice21 [21]

Answer:

The correct options are;

EFGH has 4 congruent sides

Diagonal FH bisects angles EFG and EHG

Angle FEH is congruent to angle FGH

Step-by-step explanation:

1) Given that for a reflection, we have;

The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection

Therefore;

The distance of the point E from the line HF = The distance of the point G from the line HF

Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)

We can show that from the length of a line given by the equation $l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$ , that the length EH ≅ GH and EF ≅ GF

Therefore since we are given that EH = EF, we have;

EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides

2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;

ΔEHF ≅ ΔGHF

∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent

Similarly, ∠GFH ≅ ∠EFH

Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF

Therefore, diagonal FH bisects angles EFG and EHG

3) Given that ΔEHF ≅ ΔGHF, we have;

Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent

7 0

3 years ago