Since posters cost 9 dollars each and picture frames cost 15, it would be multiplication.
The expression would be 9(6)+15(6) or 9x6+15x6.
You have to multiply these numbers. 9 times 6 would be 54. 15 times 6 would be 90.
Now, we need to add these together. 54 plus 90 would be 144.
The total cost for 6 framed posters would be $144.
mr. John is shopping for new Apple eyes at a store all lights are on sale for 10% off sales tax is 7% which expression could mr. Jones use to calculate the total cost any wise X fun cost of the item the original price is $100 equal 100 and see what toys will give you the correct price
Evaluate f(1) and g(1)
f(1)=2(1)^2-1+5=2(1)+4=2+4=6
g(1)=3(1)^2-3(1)-2=3(1)-3-2=3-5=-2
f(1)+g(1)=6-2=4
h(1)=4
Multiply the diameter by PI which is 3.14 so that means the circumference would be 15.7.
Answer: option 2 describes best
Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.
Step 1: (6x3 – 22x2) – (9x + 33)
Step 2: 2x2(3x – 11) – 3(3x + 11)
Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?
Marisol should realize that her work shows that the polynomial is prime.
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).
According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.
In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)
Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as
6x^3 – 22x^2 – 9x + 33 after opening the brackets.
