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3 years ago

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There are 31 chocolates in a box, all identically shaped. There 5 are filled with nuts, 14 with caramel, and 12 are solid chocol

ate. You randomly select one piece, eat it, and then select a second piece. Find the probability of selecting a solid chocolate candy followed by a nut candy.

1 answer:

jeyben [28]3 years ago

4 0

Answer:

Step-by-step explanation:

You will be more likely to eat one with caramel

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HELP PLEASE BE QUICK

natka813 [3]

Answer:

Part 7) $AB=27\ units$

Part 8) $x=1.7\ units$

Step-by-step explanation:

Part 7) Find the length of AB

we know that

The<u><em> two tangent theorem</em></u> states that if we draw two lines from the same point which lies outside a circle, such that both lines are tangent to the circle, then their lengths are the same

so

In this problem, applying the two tangent theorem

AB=BC

substitute the given values

$15x-3=10x+7$

solve for x

$15x-10x=7+3\\5x=10\\x=2$

Find the length of AB

$AB=15x-3$

substitute the value of x

$AB=15(2)-3=27\ units$

Part 8) we know that

If CD is tangent to circle E at point C

then

Line segment CD is perpendicular to line segment EC (radius) and CDE is a right triangle

so

Applying the Pythagorean Theorem in the right triangle CDE

$DE^2=CD^2+EC^2$

substitute the given values

$2^2=x^2+1^2$

solve for x

$4=x^2+1\\x^2=3\\x=1.7\ units$

6 0

3 years ago

HELP‼️12 Points

TiliK225 [7]

150 times 96 divided by 2 and I believe that’s your answer. 7200 meters

7 0

3 years ago

Read 2 more answers

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim

prohojiy [21]

Using the z-distribution, it is found that a sample size of 3,385 is required.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 98% confidence level, hence $\alpha = 0.98$ , z is the value of Z that has a p-value of $\frac{1+0.98}{2} = 0.99$ , so the critical value is z = 2.327.

We have no prior estimate, hence $\pi = 0.5$ is used, which is when the largest sample size is needed. To find the sample size, we solve the margin of error expression for n when M = 0.02, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.5(0.5)}{n}}$

$0.02\sqrt{n} = 2.327 \times 0.5$

$\sqrt{n} = \left(\frac{2.327 \times 0.5}{0.02}\right)$

$(\sqrt{n})^2 = \left(\frac{2.327 \times 0.5}{0.02}\right)^2$

n = 3,385.

A sample size of 3,385 is required.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0

2 years ago

A polynomial function has -5+√3t as a root. Which of the following must also be a root of the function? a) -5-√3t b) -5+√3t c) 5

juin [17]

Answer:

a

Step-by-step explanation:

Radical roots occur as conjugate pairs

Given - 5 + $\sqrt{3}$ t is a root , then

- 5 - $\sqrt{3}$ t is also a root → a

4 0

4 years ago

The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st

I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413) = 0.008$

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻' be a random variable in Normal distribution

Let X⁻ = 325,000

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{325000-290000}{\frac{145000}{\sqrt{100} } } = 2.413$

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413)$

= 0.5 - A(2.413)

= 0.5 - 0.4920

= 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413) = 0.008$

6 0

3 years ago