Question

what is the equation line that is parallel to the line y = 1/3x +4 and passes through the point (6,5)?

Answer 1

Answer:

equation of the parallel line will be $y=\frac{1}{3}x+3$.

Step-by-step explanation:

If the two lines have been given as y = mx + c

and y = m'x + c'

Where m and m' are the slopes of the given lines.

If these lines are parallel to each other then slopes of the lines will be same (m = m').

Equation of the given line is y = $\frac{1}{3}x+4$ with he slope = $\frac{1}{3}$

Then slope of a line parallel to this line m = $\frac{1}{3}$

Equation of the parallel line will be $y=\frac{1}{3}x+c$

Since the line passes through a point (6, 5)

Then $5=\frac{1}{3}\times (6)+c$

5 = 2 + c

c = 5 - 2

c = 3

Therefore, equation of the parallel line will be $y=\frac{1}{3}x+3$

Answer 2

The answer to this question is y=1/3x+3



I hope this helps!!!!!!!!!!!