<h3 /><h3>
</h3><h3>4 and 3 are answers</h3>
Answer:
b = 80
Step-by-step explanation:
Given that,
x² + bx - 81
To find,
value of b
What is factorable?
A polynomial equation with highest degree 2 is if factorable when
- we can find two terms which when multiples = -81x², <em> ( x² * - 81 = -81x² ) </em>
- and when add = bx
possible factors:
- -1x * 81x = -81x² (Accepted)
- 1x * -81x= -81x² (rejected)
- 9x * -9x = -81x² (rejected)
- -9x * 9x = -81x² (rejected)
Only when -1x , 81x is added -1x + 81x = 80x
so, bx = 80x
b = 80
<h3>The equation is x² + 80x - 81</h3>
Answer:
h= (V/πr²)(3)
Step-by-step explanation:
6x=18 (2x+5) x=6x+15. x-15=6x 5x=15 x=3
Yes it is. It is the only even number that is prime that is multiplied by 1.
