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3 years ago

Use >, <, or = to complete the statement.

Mathematics

2 answers:

nalin [4]3 years ago

6 0

It should be |-10| < |11| which I think is option C?

Sladkaya [172]3 years ago

6 0

C is the correct answer i believe

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Does 38 minus 15 and 15 less than 38 mean the same thing? Explain

lana [24]

Answer:

Step-by-step explanation:

38 minus 15

38 - 15

15 less than 38

15 < 38

7 0

3 years ago

Read 2 more answers

Amswer in its lowest terms 5 3/5 + 2 1/10

Nataly [62]

$5 \frac{3}{5} + 2 \frac{1}{10} \\ = \frac{28}{5} + \frac{21}{10} \\ = \frac{56}{10} + \frac{21}{10} \\ = \frac{77}{10} \\ = 7 \frac{7}{10}$

Hope it helps and is useful :)

3 0

2 years ago

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Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: ordinary differential equation ode integration separable variables initial value problem differential integral calculus

7 0

3 years ago

Which expressions are equivalent to -6z+ (-5.5) +3.5z + 5y - 2.5?

Molodets [167]

Answer:

what the heck its too much to me

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Mariana plans to visit an amusement park where she must pay for admission and purchase tickets to go on the rides. Mariana wants

Ivanshal [37]

Answer: The number 12 represents admission charge in Mariana's equation.

Step-by-step explanation:

As per given ,

Total cost = ( Charge per ticket) (Number of tickets) + (Admission fees) (i)

For x = Number of tickets, the total cost (c) for a day at the amusement park is given as

$c = 1.50x + 12$ (ii)

Here, 12 = Admission fees [Comparing (i) and (ii)]

Hence, the number 12 represents admission charge in Mariana's equation.

3 0

3 years ago