d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
24+8 = 30
30 - 12 = 18
18-9 = 8
There are 8 cards left in the stack
Answer:
a. Categorical
b. Quantitative
c. Categorical
d. Categorical
e. Quantitative
Step-by-step explanation:
a.
Month of year with most reservations is a qualitative or categorical variable because it can't be represented numerically in a meaningful way. For example, with most reservations month of a year can be June or July.
b.
Airbnb's total annual profit is a quantitative variable because it can be presented in numerical form and mathematical operation can be meaningfully interpreted.
c.
Type of rental on Airbnb is a qualitative or categorical variable because it can't be represented numerically in a meaningful way. Also, it can be divided into categories whole house, private room and shared room etc.
d.
Unique 10-digit reservation number is a qualitative or categorical variable as these exists in numerical form but these numbers are used only as identifiers. The mathematical operation on these numbers can't be meaningfully be interpreted.
e.
Number of house rentals is quantitative variable because it can be presented in numerical form and mathematical operation can be meaningfully interpreted.
Answer:
x =
Step-by-step explanation:
If both the triangles ΔABC and ΔBCD are congruent,
Corresponding sides of both the triangles will be proportional.
5x(4x + 3) = (5x - 2)(3x + 10)
20x² + 15x = 15x² + 50x - 6x - 20
20x² + 15x = 15x² + 44x - 20
20x² - 15x² = 44x - 15x - 20
5x² = 29x - 20
5x² - 29x + 20 = 0
5x² - 25x - 4x + 20 = 0
5x(x - 5) - 4(x - 5) = 0
(5x - 4)(x - 5) = 0
(n-1)+n+(n+1)
With n as the middle of 3 integers, n-1 is the integer just before n and n+1 is the integer just after n.