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Elena L [17]
3 years ago
6

Please help and provide as much detail as possible! Thank you!!

Mathematics
1 answer:
solniwko [45]3 years ago
3 0
34 + (2x2days) + (-1x2) So far it would equal 36$ stock then last day is -3 so 33$ is the stock.

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<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-4x%20%2B2" id="TexFormula1" title="2x^{2} -4x +2" alt="2x^{2} -4x +2" align="a
Lostsunrise [7]

2 {x}^{2}  - 4x + 2 \\  \\ 2(x  {}^{2} - 2x + 1 )\\    \\ 2(x - 1)  {}^{2}

7 0
2 years ago
Read 2 more answers
A baseball team wants a pitcher no more 150 innings during a season. So far, the pitcher has pitched <img src="https://tex.z-dn.
butalik [34]

Answer:

C. 6 because any answer besides that is too low or too high.

Step-by-step explanation:

110.25 pitches so far- 150 at max. 5.75 pitches per game.

4: 4x5.75 = 23

110.25 + 23 = 133.25

5. 5x5.75 = 28.75

110.25 + 28.75 = 139

6: 6x5.75 = 34.5

110.25 + 34.5 = 144.75

7: 7x5.75 = 40.25

110.25 + 40.25 = 150.50 > which rounds up to 151

5 0
3 years ago
What is 9/14 + 2/7 + 1/2
goldfiish [28.3K]
9/14 stays the same

2/7 turns into 4/14

1/ into 7/14

all of them added is 20/14

simplified is 1 3/7

8 0
3 years ago
Read 2 more answers
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

The bulbs should be replaced each 1436.9 hours.

6 0
3 years ago
True or false.200centimeters=2meter
katovenus [111]

Answer:

<h2>True</h2>

Step-by-step explanation:

1 meter = 100 centimeters

therefore 2m = 2(100cm) = 200cm

6 0
3 years ago
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