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grin007 [14]
3 years ago
11

How many triangles exist with the given angle measures? 80°, 50°, 50°

Mathematics
2 answers:
Alona [7]3 years ago
7 0
<span>More then one triangle exists in the given angle measures! Hope This Helps!!! :)</span>
<span />
AfilCa [17]3 years ago
5 0
80°, 50°, 50° Exactly one unique triangle exists with the given angle measures. No triangle exists with the given angle measures. More than one triangle exists with the given angle measures.
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1) Give 5 examples of a difference of two perfect squares
Katyanochek1 [597]

ᴀɴsᴡᴇʀ:

<u>1.Example, x²-25 can be factored as (x+5)(x-5).</u>

<u> </u>

<u>2.This method is based on the pattern (a+b)(a-b)=a²-b², which can be verified by expanding the parentheses in (a+b)(a-b).</u>

<u> </u>

<u>3.When an expression can be viewed as the difference of two perfect squares, i.e. a²-b², then we can factor it as (a+b)(a-b). For example, x²-25 can be factored as (x+5)(x-5).</u>

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs!

☞︎︎︎ᴄᴀʀʀʏ ᴏɴ ʟᴇᴀʀɴɪɴɢ☜︎︎︎

8 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
which statement is true about the equations –3x 4y = 12 and x1/4 – 1/3y = 1? the system of the equations has exactly one solutio
finlep [7]
If you would like to solve the system of equations, you can do this using the following steps:

-3x + 4y = 12
x * 1/4 - 1/3 * y = 1 ... x * 1/4 = 1 + 1/3 * y ... x = 4 + 4/3 * y
_____________
<span>-3x + 4y = 12
</span>-3 * (4 + 4/3 * y) + 4y = 12
-12 - 4y + 4y = 12
-12 = 12
-12 - 12 = 0
-24 = 0

The correct result would be: <span>the system of the equations has no solution; the two lines are parallel.</span>
4 0
3 years ago
Which should be calculated first to solve this story problem?  Marta has had a health club membership for 5 weeks. She goes to t
kipiarov [429]
The answer will be C. the total number of hours Marta spends swimming each visit. Hope it help!
4 0
3 years ago
Find the volume of each ball. use the formula. where v is the volume and r is the radius. record the volume in table A of your s
pochemuha

Answer:

The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


Step-by-step explanation:

Given: The radius of the tennis ball is 2.1cm and the radius of thr golf ball is 2.0cm. the formula is V=4πr(to the 3rd power) /3 .

To find: Volume of tennis ball and golf ball .

Formula used: Volume = \frac{4 π r^{3} }{3} .

 pi(π) = \frac{22}{7} .

Explanation : We are given that

                     Radius of the tennis ball = 2.1 cm

                    radius  of the golf ball =2.0 cm.

We need to find the volume of each ball

So , plugging the given values of radius in above formula

Volume of the tennis =\frac{4*22(2.1)^{3} }{3*7}

On simplification we get, volume of tennis ball = 38.808 cm^{3}

Volume of the golf ball=\frac{4*22(2.0)^{3} }{3*7}

On simplification we get, volume of golf ball = 33.523 cm^{3}

Therefore , The volume of tennis ball = 38.808 cm^{3}.

                          Volume of golf ball = 33.523 cm^{3}.


7 0
3 years ago
Read 2 more answers
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