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2 years ago

9

Is a acute triangle regular?

2 answers:

mixas84 [53]2 years ago

7 0

Answer:

An equilateral triangle may also be called a "regular" triangle. (A "regular" polygon has all equal sides and all equal angles.)An acute triangle has all angles measuring less than 90º. Note: It is possible for an acute triangle to also be scalene, isosceles, or equilateral.

Step-by-step explanation:

hope this helped and can u plz mark me brainlest

erastovalidia [21]2 years ago

5 0

An acute triangle is a triangle with angles under 90 degrees! not sure what you mean by regular but i hope this definition helped

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Solnce55 [7]

Answer:

Look at the answers bolded below

Step-by-step explanation:

To get the reference angle, just subtract 115° from 180°

180 - 115 = 65

So the reference angle is 65°

I'm not sure how many coterminal angles you need, but to get them you could just add or subtract 360°.

For example, a positive coterminal angle could be:

115 + 360 = 475°

a negative coterminal angle could be:

115 - 360 = -245°

Hope this helped :)

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2 years ago

(12) In a relay race, Mia ran 1.43 kilometers. Then she passed the baton to Gerald, who ran an

BigorU [14]

Answer:

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Step-by-step explanation:

To find out how many kilometres they ran in all you have to do 1.43+2.7 =4.13

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3 years ago

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Helen [10]

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2 years ago

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ANTONII [103]

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Step-by-step explanation:

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1 year ago

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bulgar [2K]

Answer:

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

Step-by-step explanation:

Given

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

Required

Fill in the gaps

Going by the given parameters, we have that

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

$x^2 - 9x + 8$ , when factorized is $(x-1)(x-8)$

Hence; the expression becomes

$\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}$

Combine Fractions

$\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}$

Simplify the denominators

$4x + 2 = A + B$

By direct comparison

$A = 4x$

$B = 2$

Hence, the complete expression is

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

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3 years ago

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