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dusya [7]
3 years ago
13

Two segments are ______ coplanar A.) always B.) sometimes C.) never

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
8 0
A because  coplanar means in the same plane.
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Which linear inequality is represented by the graph?
aalyn [17]

Answer:

y ≤ 1/3 x - 1.3.

Step-by-step explanation:

First find the equation of the line:

The slope = (-0.3 - (-1.3) / (3 - 0).

= 1/3 so the equation is y = 1/3x + b where b is a constant.

b is the y-intercept which is the value of y when x  = 0 . We see that it is -1.3 ( from the point 0, -1.3).

Since the line is continuous and the shading is below this line the inequality sign is 'less than or equal to',  ≤.

8 0
3 years ago
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The area of a triangle is 80x^5y^3. The height of the triangle is x^4y. What is the length of the base of the triangle?
svetoff [14.1K]
Area of a triangle is given by 1/2bh where b is the base and h is the perpendicular height of the triangle.
The area is 80x∧5y³ and the height is x∧4y
Thus; 80x∧5y³ = 1/2(x∧4y) b
         160x∧5y³ = (x∧4y)b
                  b = (160x∧5y³)/ x∧4y)
                  b = 160xy²
Therefore, the base of the triangle is 160xy²
7 0
3 years ago
Read 2 more answers
A contractor has two choices for billing a completed job. · $500 flat rate, regardless of the number of hours worked · $20 per h
pickupchik [31]

Answer:

The solution (25, 20) tells the contractor the number of hours on a job where the hourly rate is the same for both billing options.

Step-by-step explanation:

5 0
2 years ago
NEED MATH HELP ASAP
Dafna1 [17]

Answer:

2

Step-by-step explanation:

Divide the 2nd term by the 1st to find the common ratio or n.

4 0
4 years ago
Can anyone tell me why by direct substitution of x, the equation (circled ones) equals to the indeterminate form, 0/0? When you
Katena32 [7]

Answer:

See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

hx=15

Dividing both sides by h:

x=15/h

For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

225/h^2-k=0

k=225/h^2

So if we wanted to evaluate the following limit:

Lim x->15/h ( x^2-k ) / ( hx-15 )

Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

Lim x->3 ( x^2-k ) / ( hx-15 )

Comparing the two limits h=5 and k=225/h^2=225/25=9.

3 0
3 years ago
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