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JulijaS [17]
4 years ago
14

What is the minimum and maximum

Mathematics
1 answer:
erastovalidia [21]4 years ago
6 0
It is the bigger and smallest va,lue of the function
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Am I correct on #13? ONLY REAL ANSWRS OR YOULL GET REPORTED
drek231 [11]

Answer:

Yeah

Step-by-step explanation:

8 0
4 years ago
V / -0.8 +14=39 plssss help this is literally so hard ​
Nat2105 [25]
<h2><u>Answer:</u></h2><h2> \boxed{\boxed{\sf~v=-20}}</h2><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Subtract 14 from both sides:</h3>
  • 14-14= Cancels Out
  • 39-14=25

<em>  - We do this because we have to get 2 variables/numbers on each side of the equals, and the only way to do so is to cancels other numbers out by doing the opposite of what we see. </em>

<u>Equation at the end of Step 1: </u>

  • v ÷ -0.8=25

<h3>2.) Multiply both sides by −0.8:</h3>
  • -0.8 × -0.8= Cancels Out
  • 25 × -0.8=-20

______________________________

3 0
3 years ago
15. For each of the following, write the probability as the intersection of two events. Then, indicate whether the two events ar
LuckyWell [14K]

Answer:

Step-by-step explanation:

a. The probability of selecting a 6 from the first draw and a 7 on the second draw when two balls are selected without replacement from a container with 10 balls numbered 1 to 10

Not independent because without replacement

Prob for both = \frac{1}{10} \frac{1}{9} \\=\frac{1}{90}

b. The probability of selecting a 6 on the first draw and a 7 on the second draw when two balls are selected with replacement from a container with 10 balls numbered 1 to 10

Here independent because with replacement makes probability independent.

Prob for both = P(A) *P(B) = \frac{1}{10} *\frac{1}{10} \\=\frac{1}{100}d

c. The probability that two people selected at random in a shopping mall on a very busy Saturday both have a birthday in the month of June. Assume that all 365 birthdays are equally

likely, and ignore the possibility of a February 29 leap-year birthday.

Here independent because one person birthday will not affect the other person birthday

Prob for both = (\frac{30}{365})^2\\ =\frac{25}{5329}

d. The probability that two socks selected at random from a drawer containing 10 black socks and 6 white socks will both be black

Prob for I sock black = 10/16 and II sock black if first sock is black = 9/15

Hence not independent

Prob for both = \frac{10C2}{16C2} \\=\frac{3}{8}

 

 

5 0
4 years ago
Consider the equation m=
OLga [1]

Answer:

M= 125

Step-by-step explanation:

Hope it helped! Plese mark brainliest!! Have a nice night!

8 0
3 years ago
PLS HELP ME FOR THIS QUESTION
Sergeeva-Olga [200]

Answer: DO you have any options that can help me answer it?

Step-by-step explanation:


6 0
3 years ago
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