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Sloan [31]
3 years ago
13

Walgreens is offered a chain discount on cosmetics from Libby Corp. of 8/5/2; Roma Company offers a chain discount of 7/6/4. Wha

t is the highest discount offered?
.14348



.839232



.85652



.160768



None of these
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer: 0.0160768

Step-by-step explanation:

Let the marked price of the cosmetic be 100.

From the question,

Walgreens is offered a chain discount on cosmetics from Libby Corp. of 8%, 5% and 2%. The selling price of the cosmetic after the chain discount will be:

100 × (1 - 8/100) × (1 - 5/100) × (1 - 2/100)

= 100 × (1 - 0.08) × (1 - 0.05) × (1 - 0.02)

= 85.652

Discount = Marked price - Selling price

Discount = 100 - 85.652

Discount = 14.348

Discount percent = 14.348% = 0.14348

Roma Company offers a chain discount of 7%, 6% and 4%.

The selling price of the cosmetic after the chain discount will be:

100 × (1 - 7/100) × (1 - 6/100) × (1 - 4/100)

= 100 × (1 - 0.07) × (1 - 0.06) × (1 - 0.04)

= 83.9232

Discount = Marked price - Selling price

Discount = 100 - 83.9232

Discount = 16.0768

Discount percent = 16.0768% = 0.0160768

The highest discount offered is 0.0160768.

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Nataly [62]

Given:

Number of red marbles = 4

Number of blue marbles = 8

Number of yellow marbles = 6

Number of green marbles = 2

To find:

The probability of getting a blue marble then a red marble, i.e., P(blue, red).

Solution:

Using the given information,

The total number of marbles = 4+8+6+2

                                                = 20

Probability of getting a blue marble in first draw is

P(Blue)=\dfrac{\text{Number of blue marbles}}{\text{Total number of marbles}}

P(Blue)=\dfrac{8}{20}

P(Blue)=\dfrac{2}{5}

Maria selects a marble, puts it back and then selects a second marble. It means the total number of marbles remains the same.

P(red)=\dfrac{\text{Number of red marbles}}{\text{Total number of marbles}}

P(red)=\dfrac{4}{20}

P(red)=\dfrac{1}{5}

Now, the probability of getting a blue marble then a red marble is

P(blue,red)=\dfrac{2}{5}\times \dfrac{1}{5}

P(blue,red)=\dfrac{2}{25}

Therefore, the required probability P(blue, red) is \dfrac{2}{25}.

5 0
3 years ago
What is the fifth term of the sequence whose first term is 10 and whose common ratio is 1/2?
Alborosie

Answer:

\frac{5}{8}

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

here a₁ = 10 and r = \frac{1}{2}, thus

a_{5} = 10 × (1/2)^{4} = 10 × \frac{1}{16} = \frac{5}{8}

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3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
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The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

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put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

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In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

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3 years ago
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Step-by-step explanation:


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3 years ago
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