The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Answer:
I believe it is 6.
Step-by-step explanation:
C. 2-2-2-3-3 because they are all prime numbers. If you have another problem like this just use the prime number tree. Hope this helps
Answer:
Step-by-step explanation:
For that transformation you just have to use polar coordinates, notice that when you use polar coordinates the radius is constant when the angles varies and the angle is constant when the radius varies. Therefore your transformation would be just
.
Answer:
B
Step-by-step explanation:
The equation is in slope-intercept form, so the slope is the coefficient of x. Since the coefficient of x is negative, so is the slope.
