if PLAN A is cheaper than PLAN B then,
P (A) < P (B)
30+0.01t < 20+0.05t (subtract 0.05t from both sides)
29.95-0.04t < 19.95 (subtract 29.95 from both sides)
-0.04t < -10 (divide both sides by -0.04)
t > 250
So plan A is cheaper than plan B when you send more than 250 texts.
Hope it helps.
Answer:
0.1469
Step-by-step explanation:
Given from the question;
Mean=8.4 hrs=μ
Standard deviation=1.8 hrs=δ
Sample size, n=40
Let x=8.7
z=(x-μ)÷(δ÷√n)
Find z(8.7)
z=(8.7-8.4)÷(1.8÷√40)
z={0.3×√40}÷1.8=1.05409
z=1.0541
Read from the standard normal probabilities table
P(z>1.0541)
=0.1459
(b). → Simplify: [{5^(x-+1) + 5^x}/{6×5^x}]
= [{5^(x+1+x)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1)}/{6×5^x}]
= [{5^(2x+1-x)}/6]
= [{5^(x+1)}/6]Ans.
(c). 4a³b²
= 4(3)³(-2)²
Since, a = 3 and b = -2.
so,
= 4(3*3*3)(-2*-2)
= 4(27)(4)
= 108(4)
= 432Ans.
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simplify the equation simplify x^5/8/x^1/6..
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Additive identity property
