= 0.3133
Given: μ = 560
σ = 90
To find: P (490 < X < 560)
Normal distributions are symmetric, unimodal, and asymptotic. A normal distribution is determined by two parameters the mean and the variance. A normal distribution with a mean of 0 and a standard deviation of 1 is called a standard normal distribution. It's always easy to solve questions in terms to standard normal
Hence, converting normal distribution to standard normal gives:
P(490 < X < 560) = ≤
= P(0 ≤ Z < 0.888)
= P (z<0.89) - P(z ≤ 0)
Using standard normal table,
= 0.8133 - 0.5
P(490 < X < 560) = 0.3133
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Answer:
f(x)^-1 = x/4
Step-by-step explanation:
f(x)=4x
inverse
x = 4y
rewrite
4y = x
y = x/4
Answer:
f(x)^-1 = x/4
2p^2 + 3p - 4 - (-2p^2 - 3p + 4) =
2p^2 + 3p - 4 + 2p^2 + 3p - 4 =
4p^2 + 6p - 8 <==
Answer:
1. d < 10
Step-by-step explanation:
Hi there !
8 > d - 2 | +2
8 + 2 > d - 2 + 2
10 > d
d < 10
Good luck !