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Leni [432]
3 years ago
6

Twice the length of the rectangle exceeds three times the width of the rectangle by one centimeter and if one-third of the diffe

rence of the length and the width is one centimeter.find the dimension.​
Mathematics
2 answers:
Murljashka [212]3 years ago
4 0

Answer:

The length of a rectangle is twice the width. The number of square units in it's area is four times the number of units in it's perimeter.

Step-by-step explanation:

marishachu [46]3 years ago
3 0
The length of rectangle is twice the width
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F(x) = | 3x+1 | find the vertex of value function
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Answer:

The vertex is the point (-\frac{1}{3},0)

Step-by-step explanation:

we know that

The general form of an absolute value equation is

y=a\left|x-h\right|+k

The variable a tells us how far the graph stretches vertically, and whether the graph opens up or down. The variables  h, and k, tell us how far the graph shifts horizontally and vertically

The vertex is the point (h,k)

we have

f(x)=\left|3x+1\right|

Rewrite the expression (3x+1)

(3x+1)=\frac{3}{3} (3x+1)=3(x+\frac{1}{3})

substitute

f(x)=\left|3(x+\frac{1}{3})\right|

f(x)=3\left|(x+\frac{1}{3})\right|

a=3\\h=-\frac{1}{3}\\k=0

therefore

The vertex is the point (-\frac{1}{3},0)

see the attached figure to better understand the problem

4 0
4 years ago
PLEASE HELP! 
NNADVOKAT [17]

D is ur answer bro good luck


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