Step-by-step explanation:
or,(x-2)(x-4)+(3x-11)(x-3)/(x-3)(x-4)=(4x+13)/(x+1)
or,x^2-4x-2x+8+3x^2-9x-11x+33/x^2-4x-3x+12=(4x+13)/(x+1)
or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)
or,4x^2-26x+41/x^2-7x+12=(4x+13)/(x+1)
or, (x+1)(4x^2-26x+41)=(4x+13)(x^2-7x+12)
or,4x^3-26x^2+41x+4x^2-26x+41=4x^3-28x^2+48x+13x^2-91x+156
or,-26x^2+4x^2+28x^2-13x^2+41x-26x-48x+91x=156-41
or,-7x^2+58x=115
or,-7x^2+58x-115=0
or,-(7x^2-58x+115)=0
or,7x^2-58x+115=0
or,7x^2-(35+23)x+115=0
or,7x^2-35x-23x+115=0
or,7x (x-5)-23 (x-5)=0
or, (x-5)(7x-23)=0
Either, Or,
(x-5)=0 (7x-23)=0
or,x=0+5 or,7x=23
:x=5 :x=23/7
Hence,x=5 or 23/7
Step-by-step explanation:
Given expression;
2x + y = -5;
The given equation must be written in a form where the slope is the negative inverse of the given one.
A line perpendicular to another will have a negative inverse slope.
2x + y = -5
Equation of a straight line is generally written as;
y = mx + c
y and x are the coordinates
m is the slope
c is y - intercept
2x + y = -5
y = -2x -5
The slope of the perpendicular =
So,
the new line;
y =
x -5
Any line with slope of
will be perpendicular
Sooooooooooooooo X= 28 and Y= 47
Answer:

Step-by-step explanation:
To find the gradient (slope) of the given <u>linear relation</u>, use <u>arithmetic operations</u> to isolate y:
Given relation:

Add 5x to both sides:


Divide both sides by 3:


<u>Slope-intercept form of a linear equation</u>

where:
- m is the slope (gradient)
- b is the y-intercept
Comparing the rewritten equation with the slope-intercept formula, the gradient (slope) of the given linear relation is ⁵/₃.
Learn more about linear equations here:
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