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valentinak56 [21]
3 years ago
8

Which of the following is a solution of x^2 2x = −2?

Mathematics
1 answer:
dem82 [27]3 years ago
3 0
x^2+2x=-2\\
x^2+2x+1=-1\\
(x+1)^2=-1\\
x+1=\sqrt{-1}\vee x+1=-\sqrt{1}\\
x=-1+i \vee x=-1-i

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A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
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Allushta [10]

Answer:

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Step-by-step explanation:

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2 years ago
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Write the equation of a circle with center (7.0) with radius 3.
harina [27]

Answer:

2.3

Step-by-step explanation:

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3 years ago
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Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
notsponge [240]

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

length = w + 33, height = w - 13

Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423

When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

Rate = 10118 - 5423 = 4695 in³/in

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0
2 years ago
Solve. -2 1/4 ÷ (-1 1/2)
Pie

Answer:

=21/22

(Decimal: 0.954545)

hope i helped -lvr

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