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frez [133]
3 years ago
7

Marco and Drew stacked boxes on a shell. Marco lifted 9 boxes and Drew lifted 14 boxes. The boxes that Drew lifted each weighed

8 lb
less than the boxes Marco lifted.
Let m represent the weight of the boxes that Marco lifted,
Which expression represents the total number of pounds Drew litted?
14 (m – 8)
m - 8
112m
9 (m + 8)
Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

If m = the weight of boxes that marco lifted, and each box that drew lifted was 8 lbs less than marcos boxes, then you would multiply the total number of boxes that drew lifted by the weight of marcos total boxes - 8 or 14(m-8)

Step-by-step explanation:

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5x+4.27xy+20y+36y-19x+9.11
mote1985 [20]
So what I did was the terms that were alike like this: (5x -19x)+(20y+36y)+4.27xy+9.11. Then I simplified and got -14x+56y+4.27xy+9.11. The terms 4.27xy and 9.11 were not in ()'s because they were the only ones with an alike term. Hope that helps and also try to doing the steps and see what you get. If you get it wrong look to see where you messed up and try again! If I am wrong please notify me, I would appreciate it! 
6 0
3 years ago
Which one of these formulas describes the following sequence?<br><br> 1,5,12,22,35
kati45 [8]

We can find a formula for nth term of the given sequence as follows:

1, 5, 12, 22, 35

The 1st differences between terms:

4, 7, 10, 13

The 2nd differences :

3, 3, 3

Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form: a n^2 + b n + c, where c is a constant. The coefficients a, b, and the constant c can be found.

We can form the following 3 equations with 3 unknowns a, b, c:

1 = a\cdot1^2 + b\cdot1 + c\\5 = \cdot2^2 + b\cdot2 + c\\12 = a\cdot3^2 + b\cdot3 + c

Solving for a, b, c, we get:

a = 3/2, b = -1/2, c = 0

Therefore, the nth term of the given sequence is:

\boxed{ a_n = \dfrac{3}{2}n^2- \dfrac{1}{2} n}

7 0
3 years ago
Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha
Pavel [41]

Answer:

(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14.

(Expand to obtain an equivalent expression for the sphere: x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0)

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}.

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}.

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between \left(x_1, \, y_1, \, z_1\right) and \left(x_2, \, y_2, \, z_2\right) would be:

\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right).

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}.

The equation for a sphere of radius r and center \left(x_0,\, y_0,\, z_0\right) would be:

\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2.

In this case, the equation would be:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2.

Simplify to obtain:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56.

Expand the squares and simplify to obtain:

x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0.

8 0
3 years ago
Solve x+4=10 A.x=2 B.x=3 C.x=6 D.x=14
labwork [276]

Answer:

C. x = 6

Step-by-step explanation:

6 + 4 = 10

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%3Dx%2B3y%3Dx-1" id="TexFormula1" title="y=x+3y=x-1" alt="y=x+3y=x-1" align="absmiddle" class
Dominik [7]

Answer:

y = x + 3y = x - 1

Step-by-step explanation:

Just graph them!

Hope I could help.

5 0
3 years ago
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