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frez [133]
3 years ago
7

Marco and Drew stacked boxes on a shell. Marco lifted 9 boxes and Drew lifted 14 boxes. The boxes that Drew lifted each weighed

8 lb
less than the boxes Marco lifted.
Let m represent the weight of the boxes that Marco lifted,
Which expression represents the total number of pounds Drew litted?
14 (m – 8)
m - 8
112m
9 (m + 8)
Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

If m = the weight of boxes that marco lifted, and each box that drew lifted was 8 lbs less than marcos boxes, then you would multiply the total number of boxes that drew lifted by the weight of marcos total boxes - 8 or 14(m-8)

Step-by-step explanation:

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Amelia and Joey decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye. Amelia went first a
Alona [7]

Answer:

outer ring worth 14 pts

bull's-eye worth 74.333333 pts

Step-by-step explanation:

let the worth point of landing an arrow on the outer ring be "x" and on bull's eye be "y"

For amelia

3x + 3y = 267

For joey

4x + 3y = 281

<em>s</em><em>u</em><em>b</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>f</em><em>i</em><em>r</em><em>s</em><em>t</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>s</em><em>e</em><em>c</em><em>o</em><em>n</em><em>d</em>

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3 0
3 years ago
Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with
yan [13]

Answer:

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

<em></em>

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, s_A = 12 inches

Height of A, h_A = 8 inches

Side Length of B, s_B = 48 inches

Height of B, h_B = 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

OR

V_B is how many times bigger than V_A ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}

Here, base is square, so:

V=\dfrac{1}{3} \times s^2 \times h

Volume of pyramid A:

V_A=\dfrac{1}{3} \times s_A^2 \times h_A

\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3

Volume of pyramid B:

V_B=\dfrac{1}{3} \times s_B^2 \times h_B

\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

3 0
3 years ago
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