Step-by-step explanation:
According to the property in kite abcd ac divides bd in two equal halves.
So, from that BE = DE
![- x + 6 = 0.5x](https://tex.z-dn.net/?f=%20-%20x%20%2B%206%20%3D%200.5x)
![6 = 0.5x + x](https://tex.z-dn.net/?f=6%20%3D%200.5x%20%2B%20x)
![6 = 1.5x](https://tex.z-dn.net/?f=6%20%3D%201.5x)
![x = \frac{6}{1.5}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B6%7D%7B1.5%7D%20)
![x = 4](https://tex.z-dn.net/?f=x%20%3D%204)
Hope this helps u.
^_^❤️
Answer:
The answer is 157
Step-by-step explanation:
8/4= 8 divided by 4
5(6^2)-8/4-(7+14)
5(6^2)-8/4-(7+14)
=157
Answer is b
<span>24x2+25x−47=−8ax2−3ax+16x−47
</span><span>-3 at the end for a
</span><span>i know my stuff :)</span>
Answer:
We know by given that OC bisects the angle, which means it divides the angle AOB in two equal parts. So,
![m \angle AOB = 3x +5 + 3x +5 =6x+10](https://tex.z-dn.net/?f=m%20%5Cangle%20AOB%20%3D%203x%20%2B5%20%2B%203x%20%2B5%20%3D6x%2B10)
If
, then we use this value to find each angle.
![m \angle BOC = 3x+5 =3(9)+5=27+5=32](https://tex.z-dn.net/?f=m%20%5Cangle%20BOC%20%3D%203x%2B5%20%3D3%289%29%2B5%3D27%2B5%3D32)
Therefore, angles BOC and AOC measure 32°.