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3 years ago

A system of linear equations contains two equations with the same slope

Mathematics

2 answers:

Rus_ich [418]3 years ago

4 0

A is the correct statement for this question

aleksandrvk [35]3 years ago

3 0

Answer: A
Explanation: because they both have the same slope they share the same graph. Whatever works for one works for the other so there can be many different (infinite) solutions

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Which is the correct stem-and-leaf plot for the data set? 11, 10, 49, 36, 35, 34, 11, 32

hram777 [196]

Answer:

The answer is B

Step-by-step explanation:

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3 years ago

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Write the set of points from −2 to 6 but excluding 3 and 6 as a union of intervals:

KengaRu [80]

Answer:

[-2,6] - {3} - {6} = [-2,3) ∪ (3,6)

Step-by-step explanation:

Union Of Intervals

Let us assume two interval A = (a,b) and C = (c,d).

Their union is written as : A ∪ C = (a,b) ∪ (c,d)

Now, if interval is written in form [a,b] ⇒ a and b are INCLUDED in interval

Also, if interval is written in form (a,b) ⇒ a and b are NOT INCLUDED in interval

Here, the given interval is [-2,6]

excluding 3 and 6 from this will give:

[-2,3) ∪ (3,6)

The first set is [-2.3) where -2 is INCLUDED but 3 is NOT INCLUDED.

The second set is (3,6) where 3 and 6 both are NOT INCLUDED.

Hence, [-2,6] - {3} - {6} = [-2,3) ∪ (3,6)

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4 years ago

a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues

DerKrebs [107]

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that $P(0) = 24000$

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

$P(t) = P(0)(1+r)^{t}$

$29000 = 24000(1+r)^{20}$

$(1+r)^{20} = \frac{29000}{24000}$

$\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}$

$1 + r = 1.0095$

$P(t) = P(0)(1+r)^{t}$

$P(t) = 24000(1.0095)^{t}$

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

$P(t) = 24000(1.0095)^{t}$

$P(100) = 24000(1.0095)^{100} = 61779$

It will have a population of 61,779 in 2000.

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3 years ago

What is 30% of 90%? A. 15 B. 27 C. 30 D. 45

Paha777 [63]

Answer:

29% of 90 = ? ... 31% of 90 = ?

1% of 90 = ?

30% × 90 =

(30 ÷ 100) × 90 =

(30 × 90) ÷ 100 =

2,700 ÷ 100 =

27;

Step-by-step explanation:

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Production process gets reduced n after sometime they stop making products

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