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xenn [34]
3 years ago
6

Imagine we are throwing a five-sided die 50 times. on average out of these 50 throws how often would the five-sided die show an

odd number
Mathematics
1 answer:
lakkis [162]3 years ago
7 0
There are 3 odd numbers on the die: 1, 3, and 5. So on a given throw you have a 3/5 chance of getting an odd number. For 50 throws that's
50•(3/5)=30
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2. Simplify 2(54−1)3 completely. Show as much work as possible for full credit.
poizon [28]

(2 \times 54 - 2)3 = 108 - 2 \times 3 = 106 \times 3 = 318

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3 years ago
Read 2 more answers
Help<br> ===================
Lorico [155]

Answer:

A = 1725 ft^2

Step-by-step explanation:

A = <u>a + b</u>  * h

        2

A = area

a = top

b = base

h = height

A = <u>a + b</u>  * h

        2

A = <u>65 + 50</u>  * 30

           2

A = 57.5 * 30

A = 1725 ft^2

4 0
2 years ago
Aaron plans to buy new flooring for his office. His office floor is a rectangle that is 7.9 meters by 6.2 meters
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He bhjjjbhggthsndbdudhdusjsjjsjhh
3 0
3 years ago
Can someone please read that and give me an answer, i’ve been stuck on it for awhile.
olya-2409 [2.1K]

Answer:

after 21 seconds

Step-by-step explanation:

Given

h = - 16t² + 272t + 1344

When the ball strikes the ground then h = 0, that is

- 16t² + 272t + 1344 = 0 ( divide through by - 16 )

t² - 17t - 84 = 0 ← in standard form

(t - 21)(t + 4) = 0 ← in factored form

Equate each factor to zero and solve for t

t - 21 = 0 ⇒ t = 21

t + 4 = 0 ⇒ t = - 4

However t > 0 thus t = 21

The ball strikes the ground after 21 seconds.

4 0
3 years ago
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