Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
The fourth option - t = 3, y = 5
Step-by-step explanation:
-8 + t becomes -5, thus t is 3 since -8 + 3 = -5.
-12 becomes -2y - 2, so we can set these equal to each other as -2y - 2 = -12 and solve from there. Add 2 to both sides, -2y = -10, then divide by -2 on both sides, y = 5.
Answer:
x=5.5
Step-by-step explanation:
LN and KM intersect and are in the same rectangle, which makes them the same line essentially. Set 49 equal to 6x+16 and then solve to get x by itself.
<h2>The third graph</h2><h3 /><h3>The graph has a slope of 2</h3><h3>and a y-intercept of -4</h3>
