Answer: Threads
Explanation: Threads are the part of the programs in the computer field. It is like the way in which the execution of the procedure/process is carried out. There are also chances of having multiple threads depending on the process.
It's like the command line as an individual which gets processed which can work in the core of the computer system.The condition in the system that there must be presence of atleast one thread .
Answer:
// program in java.
import java.util.*;
// class definition
class Main
{
// main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
// object to read input
Scanner scr=new Scanner(System.in);
System.out.print("Enter the String:");
// read string from user
String str=scr.nextLine();
System.out.print("Enter the character:");
// read character
char ch=scr.next().charAt(0);
// variable to count the occurrence of character
int char_count=0;
for(int i=0;i<str.length();i++)
{
// find the character i string
if(ch==str.charAt(i))
// increase the count
char_count++;
}
// print the count
System.out.println("count of "+ch+" in the String is:"+char_count);
}catch(Exception ex){
return;}
}
}
Explanation:
Read a string from user and assign it to variable "str".Then read a character to and assign it to variable "ch".Then Declare a variable "char_count" to count the occurrence of character in the string.Find the count of character in the string. Here upper case character is different than lower case.
Output:
Enter the String:Monday
Enter the character:n
count of n in the String is:1
Enter the String:Nobody
Enter the character:n
count of n in the String is:0
Answer :
Written in java
import java.util.Scanner;
public class Main{
public static void main(String[] args) {
int year;
Scanner scanner = new Scanner(System.in);
System.out.print("Please enter a year\n\n");
year = scanner.nextInt();
while (year < 1582) {
System.out.print("\nPlease enter a different year above 1582\n");
year = scanner.nextInt();
}
if (year % 4 == 0) {
if(year % 100 ==0 && year % 400 != 0){
System.out.println(year + " is not a leap year\n\n");
}else {
System.out.println(year + " is a leap year\n");
}
} else {
System.out.println(year + " is not a leap year\n\n");
}
}
}
Answer:
Microsoft word.
Explanation:
i am very sorry if the answer is wrong
