Answer:
Challenge-Handshake Authentication Protocol (CHAP).
Explanation:
In Computer technology, authentication can be defined as the process of verifying the identity of an individual or electronic device. Authentication work based on the principle (framework) of matching an incoming request from a user or electronic device to a set of uniquely defined credentials.
Basically, authentication ensures a user is truly who he or she claims to be, as well as confirm that an electronic device is valid through the process of verification.
In this scenario, an organization wants to implement a remote dial-in server to ensure that personnel can connect to the organization's network from remote locations. The authentication protocol must include encryption to prevent hackers from accessing the network.
Hence, the protocol which should be used is Challenge-Handshake Authentication Protocol (CHAP).
A Challenge-Handshake Authentication Protocol (CHAP) can be defined as a standard network access control protocol in which a client program dials in to a network access server to receive a random value and identification number that can only be used once.
Answer:
see explaination
Explanation:
//selective dev elements by id name
var gradeA = document.querySelector("#GradeA");
var passing = document.querySelector("#Passing");
var learning = document.querySelector("#Learning");
//function showGrades
function showGrades() {
var arr = [];
//converting string to int and inserting into array
arr[0] = parseInt(gradeA.textContent);
arr[1] = parseInt(passing.textContent);
arr[2] = parseInt(learning.textContent);
//creating json blob
var blob = new Blob(new Array(arr), {type:"text/json"});
return blob;
}
Home is the answer. Hope this helps. :)
Which language? In Java it would simply be:
int count;
Yes , it’s true. In a known-plaintext attack (kpa), the cryptanalyst can only view a small portion of encrypted data, and he or she has no control over what that data might be.
The attacker also has access to one or more pairs of plaintext/ciphertext in a Known Plaintext Attack (KPA). Specifically, consider the scenario where key and plaintext were used to derive the ciphertext (either of which the attacker is trying to find). The attacker is also aware of what are the locations of the output from key encrypting. That is, the assailant is aware of a pair. They might be familiar with further pairings (obtained with the same key).
A straightforward illustration would be if the unencrypted messages had a set expiration date after which they would become publicly available. such as the location of a planned public event. The coordinates are encrypted and kept secret prior to the event. But when the incident occurs, the attacker has discovered the value of the coordinates /plaintext while the coordinates were decrypted (without knowing the key).
In general, a cipher is easier to break the more plaintext/ciphertext pairs that are known.
To learn more about Plaintext Attack click here:
brainly.com/question/28445346
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