The way to work it is to make a table in Excel (or equivalent program) with the data of budget for every year.
This is how it should look:
<span><span><span>year
budget
</span>
<span>
0
265.1
</span>
<span>
1
277.5
</span>
<span>
2
288.9
</span>
<span>
3
303.0
</span>
<span>
4
311.3
</span><span> 5
320.4
</span><span> 6
334.5
</span><span> 7
351.2
</span>
<span>
8
368.2
</span>
<span>
9 381.7
Select both columns and inser a scatter plot graph (menu, insert, graph, scatterplot).
Now change the design of the graph to include the model. In this case I got y = 12.724 x + 262.92
x represents the number of year after 1990 and y represents the budget.
Now you can use the model to calcualte the budget when you know the year and to calculate the year when you know the budget.
For year 2001, x = 11 and y = 12.724 (11) + 262. 92 = 402.88 (which is 402,880)
This is the same year for which the budget exceeds 400,000. </span></span></span>
A=9
B=11
C=12
D=15
THE LENGTH OF THE LARGEST POSSIBLE SIDE IS
or,9+11+12+15
or,47 answer
Distance:
subtract (5,2)-(2,6) = (3,-4)
Compute the length (Pythagoras): sqrt( 3^2 + (-4)^2 ) = sqrt(25)=5
So, C!
(3,2) because it is in the direct center
Answer:
use desmo's graphing calculator that might help
Step-by-step explanation:
I don't know the answer but use this to graph
