Juanita has 3 rectangular cards that are 8 inches by 9 inches. How can she arrange the cards, without overlapping, to make one l
arger polygon with the smallest possible perimeter? How will the area of the polygon compare to the combined area of the 3 cards?
1 answer:
Answer:
Step-by-step explanation:
Given
- 3 rectangular cards
- each card is 8 inches by 9 inches
The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:
Put 3 cards together according to the length
So the smallest possible perimeter is:
8 + 8 + 8 + 8 + 8 + 8 + 9 + 9 = 66 inches as you can see in the attached photo.
The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.
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Answer:
here's the solution :-
1.) =》the base of the larger triangle is the length of shadow formed by cactus .
so, length of cactus is : 33 feet.
2.) now, jn the smaller triangle formed by liam and it's shadow : -
=》
since both triangle form 90° the bases of both the larger and smaller triangles are parallel , so the base angles of larger triangle = corresponding base angles of the smaller triangle
hence, the both triangles are similar
( by A.A postulate )
now since the both triangles are similar, the the sides will be proportional ,
=》
=》
=》
=》
so, length of the cactus = x = 22 feet