Juanita has 3 rectangular cards that are 8 inches by 9 inches. How can she arrange the cards, without overlapping, to make one l
arger polygon with the smallest possible perimeter? How will the area of the polygon compare to the combined area of the 3 cards?
1 answer:
Answer:
Step-by-step explanation:
Given
- 3 rectangular cards
- each card is 8 inches by 9 inches
The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:
Put 3 cards together according to the length
So the smallest possible perimeter is:
8 + 8 + 8 + 8 + 8 + 8 + 9 + 9 = 66 inches as you can see in the attached photo.
The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.
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hmm alrite...so 4 folks working for 8hrs in 1 day, each one does 8, 4 of them, 4*8 = 32, so, they do 32 workhours every day, now for 15 days, that'd be 32*15, or 480
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how many workhours total? well 5*6 = 30
each is working 6hrs, 5 of them, so 30 workhours
how long will it take them if they only do 30 workhours everyday?
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