Question

Solve this quadratic formula -3x^2 +16 +12

Answer 1

Solve for x over the real numbers:

-3 x^2 + 16 x + 12 = 0

The left hand side factors into a product with three terms:

-(x - 6) (3 x + 2) = 0

Multiply both sides by -1:

(x - 6) (3 x + 2) = 0

Split into two equations:

x - 6 = 0 or 3 x + 2 = 0

Add 6 to both sides:

x = 6 or 3 x + 2 = 0

Subtract 2 from both sides:

x = 6 or 3 x = -2

Divide both sides by 3:

Answer: | x = 6 or x = -2/3

Answer 2

1.). Solve this quadratic formula:

-3x^2  +    16   +    12 =====>  Solution   -3x^2      +   28

Let's simplify step-by-step.

−3x^2     +    16   +    12

Combine Like Terms:

=     −3x^2      +     16     +      12

=     (−3x^2)    +    (16    +   12)

=     −3x^2    +     28

 Answer:

=      −3x^2     +    28    

Answer  =======>           -3x^2       +      28

2).   Solve the Quadratic Formula:

-3x^2  +    16x   +    12  =====>    - ( x   -  6 ) ( 3x   +   2 )

Steps:  

-3x^2  +    16x   +    12

Factor out Common Term    -1:

- (3x^2  -   16x   -    12 )

Factor:

3x^2  -    16x   -    12:             ( x   -   6 ) ( 3x    +  2 )

x^1    =======>    -2/3

x^2   =======>   6

Answer  =========>    - (x   -   6 ) ( 3x    +   2 )

Hope that helps!!!!                                            : )